2015 Internationaux de Strasbourg – Doubles
Appearance
Doubles | |
---|---|
2015 Internationaux de Strasbourg | |
Champions | Chuang Chia-jung Liang Chen |
Runners-up | Nadiia Kichenok Zheng Saisai |
Score | 4–6, 6–4, [12–10] |
The doubles tennis tournament at the 2015 Internationaux de Strasbourg took place in Strasbourg, France, as part of the 2015 WTA Tour.
Ashleigh Barty and Casey Dellacqua were the defending champions, but chose not to participate this year.
Chuang Chia-jung and Liang Chen won the title, defeating Nadiia Kichenok and Zheng Saisai in the final, 4–6, 6–4, [12–10].
Seeds
[edit]All seeds received a bye into the quarterfinals.
- Chuang Chia-jung / Liang Chen (champions)
- Nadiia Kichenok / Zheng Saisai (final)
- Raquel Kops-Jones / Taylor Townsend (semifinals)
- Jocelyn Rae / Anna Smith (semifinals)
Draw
[edit]Key
[edit]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | C-j Chuang C Liang | 6 | 65 | [10] | |||||||||||||||||||||||
T Búa L Thorpe | 63 | 5 | M Brengle A Muhammad | 1 | 77 | [4] | |||||||||||||||||||||
M Brengle A Muhammad | 77 | 7 | 1 | C-j Chuang C Liang | 3 | 6 | [10] | ||||||||||||||||||||
3 | R Kops-Jones T Townsend | 6 | 3 | [6] | |||||||||||||||||||||||
3 | R Kops-Jones T Townsend | 6 | 6 | ||||||||||||||||||||||||
I Falconi S Rogers | 4 | 4 | I Ramialison C Sibille | 4 | 4 | ||||||||||||||||||||||
I Ramialison C Sibille | 6 | 6 | 1 | C-j Chuang C Liang | 4 | 6 | [12] | ||||||||||||||||||||
A Fomina P Krejsová | 7 | 63 | [9] | 2 | N Kichenok S Zheng | 6 | 4 | [10] | |||||||||||||||||||
C Daniels M Sammons | 5 | 77 | [11] | C Daniels M Sammons | 3 | 4 | |||||||||||||||||||||
4 | J Rae A Smith | 6 | 6 | ||||||||||||||||||||||||
4 | J Rae A Smith | 1 | 7 | [3] | |||||||||||||||||||||||
WC | A Barańska V Muntean | 2 | 2 | 2 | N Kichenok S Zheng | 6 | 5 | [10] | |||||||||||||||||||
A Cornet M Linette | 6 | 6 | A Cornet M Linette | 2 | 6 | [6] | |||||||||||||||||||||
2 | N Kichenok S Zheng | 6 | 1 | [10] |